Procedure:
To find the thickness of a piece of aluminum foil, we first used the formula for volume: V = L x H x W. We measured the length (15.50 cm) and width (8.13 cm) of the foil, leaving the height H (thickness) as the variable to solve for. For the volume of the foil, we used the expression 15.50 x 8.13 x H (126 x H). The next step was to find the mass and density to plug into the formula D=M/V. We calculated the mass, which was 0.48 grams, by weighing the foil on the scale. We then determined the density by referring to the given density of aluminum from Part I of the lab, which was 2.8 g/cm3. By plugging these three values into D=M/V, we obtained:
Finally, we solved for H and rounded to two significant figures, which was 0.0014 cm. We converted that to millimeters by multiplying it by ten and obtained our final answer for the thickness of aluminum foil, 0.014 mm.
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